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Joined 1 year ago
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Cake day: July 2nd, 2023

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  • Shared gold means no silver medal. (2 gold, 0 silver, 1 bronze)

    Shared silver means no bronze medal. (1 gold, 2 silver, 0 bronze)

    Shared bronze means shared bronze. Also some disciplines give out 2 bronze medals by default, which is the reason for the high number of bronze medals. (1 gold, 1 silver, 2 bronze)










  • neumast@lemmy.worldtoMemes@lemmy.mlScary
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    1 year ago

    $ 50

    Do you call this fifty dollars, or dollar fifty?

    Lots of stuff is written differently, than it is spoken. In case of the date it is weird, not to go from biggest to smallest or vice versa. I guess you are used to it now, but for me it would be the same as putting seconds before minutes or inches before feet.




  • Sooooo, wavelengths (λ) become longer when something moves away (redshift) and become shorter when something moves towards you (blueshift).

    For a red flag (λ0=610nm) to become a green flag (λ1=549nm), it has to move towards you quite fast. But how fast is ‘quite fast’?

    Using the formula

    flag_velocity / speed of light © = difference in wavelengths / starting wavelength

    we get

    flag_velocity = (610-549) / 610 * c = 61 / 610 * c = 1/10 * c

    This means: the flag has to move with about c/10 = 30 000 000 m/s = 108 000 000 km/h = 67 108 100 mph. Yeah, that’s quite fast.

    (Disclaimer:

    1. use info on own risk

    2. values for λ were chosen in a way to make calculations easy. There is no info on what shade of red or green the flag is. The final result will be about the same.

    3. With speeds at around 10% of c, I should use the formula considering the relativistic doppler effect… However, i wont. Thanks.)


  • Sooooo, wavelengths (λ) become longer when something moves away (redshift) and become shorter when something moves towards you (blueshift).

    For a red flag (λ0=610nm) to become a green flag (λ1=549nm), it has to move towards you quite fast. But how fast is ‘quite fast’?

    Using the formula

    flag_velocity / speed of light © = difference in wavelengths / starting wavelength

    we get

    flag_velocity = (610-549) / 610 * c = 61 / 610 * c = 1/10 * c

    This means: the flag has to move with about c/10 = 30 000 000 m/s = 108 000 000 km/h = 67 108 100 mph. Yeah, that’s quite fast.

    (Disclaimer:

    1. use info on own risk

    2. values for λ were chosen in a way to make calculations easy. There is no info on what shade of red or green the flag is. The final result will be about the same.

    3. With speeds at around 10% of c, I should use the formula considering the relativistic doppler effect… However, i wont. Thanks.)